11[4-(3-x)]+x=3(4x+4)-1

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Solution for 11[4-(3-x)]+x=3(4x+4)-1 equation:


Simplifying
11[4 + -1(3 + -1x)] + x = 3(4x + 4) + -1
11[4 + (3 * -1 + -1x * -1)] + x = 3(4x + 4) + -1
11[4 + (-3 + 1x)] + x = 3(4x + 4) + -1

Combine like terms: 4 + -3 = 1
11[1 + 1x] + x = 3(4x + 4) + -1
[1 * 11 + 1x * 11] + x = 3(4x + 4) + -1
[11 + 11x] + x = 3(4x + 4) + -1

Combine like terms: 11x + x = 12x
11 + 12x = 3(4x + 4) + -1

Reorder the terms:
11 + 12x = 3(4 + 4x) + -1
11 + 12x = (4 * 3 + 4x * 3) + -1
11 + 12x = (12 + 12x) + -1

Reorder the terms:
11 + 12x = 12 + -1 + 12x

Combine like terms: 12 + -1 = 11
11 + 12x = 11 + 12x

Add '-11' to each side of the equation.
11 + -11 + 12x = 11 + -11 + 12x

Combine like terms: 11 + -11 = 0
0 + 12x = 11 + -11 + 12x
12x = 11 + -11 + 12x

Combine like terms: 11 + -11 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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